Just a quick note to say I've done some recomputation of this. For the first four compartments, I've estimated the tapering of the bow to be an angle of 12 degrees. The water entering the hull (pependicular to the hull) would be a factor of sine 12.

For half speed, I estimate 10 knots; 17 feet per seconds, or 5.1 metres per second. So, the water flow would be 5.1 sin 12 = 1.1 metres per second.

The continuity equation would be density*area*velocity = mass rate. The area I obtained from the B&H report, to be 8.6 square feet, or 0.78 square metres. So, this yields 858 kg per second, or 0.858 cubic metres per second.

Over the 10 minutes that the ship was alledged to have cruised at half speed, this would yield nearly 515,000 kg or nearly 515 cubic metres (18600 cubic feet).

The calculations of B&H seem to be flawed, but they do give an indication of the amount of water in the hull by the time the ship stopped steaming - perhaps by condition C2 (12.00pm), which would be nearly 8,000,000 kg (8000 cubic metres). So, yes, the amount of water caued by the ram effect would be small in comparison, and it would be spread over, in this case 4 compartmens (I only did the first 4 as boiler rooms 5 and 6 seem to be more parallel to the flow of water).

So, for each compartment, neglecting the coefficient of discharge (B&H values from tables

6A-7B)

:

fore peak; damaged area = 0.6 square feet.

Water entering hull by Ram Effect=

area (0.06 sq m)

v = 1.1 metres

density = 1000 kg m^-3

Therefore mass rate = 66 kg per second

B&H mass rate = 317 kg per second

hold 1 - as before, but with an ingress area

of 1.5 square feet, or 0.32 square metres,

mass rate = 352 kg per second

B&H = 375 kg per second

hold 2:

mass rate (ram effect for 3.1 square feet/0.14 square metres) = 154 kg per second

B&H = 900 kg per second

hold 3

mass rate for 3.3 square feet (0.3 sq metres)

= 330 kg per second

B&H = 2180 kg per second

Hmmm. The values for hold 1 look a bit dodgy. I'll have another look tomorrow.

YMMV.